Data Structures & Algorithms Handson solutions cognizant (1)

Forming a Magic Square Data Structures and Algorithm Cognizant Handson Solution

In this post we are going to cover the Data Structures & Algorithms Forming a Magic Square handson solution asked in Cognizant.

Question of this handson is available here.

Steps to upload answer in GenC Platform:

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  2. Insert the below code in Hacker Rank code editor.
  3. Compile & Execute the Code.
  4. Take screenshot of successful execution.
  5. And upload the screenshot in the platform.
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.function.*;
import java.util.regex.*;
import java.util.stream.*;
import static java.util.stream.Collectors.joining;
import static java.util.stream.Collectors.toList;

class Result {

    /*
     * Complete the 'formingMagicSquare' function below.
     *
     * The function is expected to return an INTEGER.
     * The function accepts 2D_INTEGER_ARRAY s as parameter.
     */

    public static int formingMagicSquare(List<List<Integer>> s) {
    // Write your code here
    
        int[][][] possiblePermutations = {
            {{8, 1, 6}, {3, 5, 7}, {4, 9, 2}},// 1

            {{6, 1, 8}, {7, 5, 3}, {2, 9, 4}},// 2

            {{4, 9, 2}, {3, 5, 7}, {8, 1, 6}},// 3

            {{2, 9, 4}, {7, 5, 3}, {6, 1, 8}},// 4

            {{8, 3, 4}, {1, 5, 9}, {6, 7, 2}},// 5

            {{4, 3, 8}, {9, 5, 1}, {2, 7, 6}},// 6

            {{6, 7, 2}, {1, 5, 9}, {8, 3, 4}},// 7

            {{2, 7, 6}, {9, 5, 1}, {4, 3, 8}},// 8
        };
        int minCost = Integer.MAX_VALUE;
        for (int permutation = 0; permutation < 8; permutation++) 
        {
            int permutationCost = 0;
            for (int i = 0; i < 3; i++) 
            {
                for (int j = 0; j < 3; j++)
                    permutationCost += Math.abs(s.get(i).get(j) - possiblePermutations                          [permutation][i][j]);
            }
            minCost = Math.min(minCost, permutationCost);
        }
        return minCost;
    }
}

public class Solution {
    public static void main(String[] args) throws IOException {
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

        List<List<Integer>> s = new ArrayList<>();

        IntStream.range(0, 3).forEach(i -> {
            try {
                s.add(
                    Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
                        .map(Integer::parseInt)
                        .collect(toList())
                );
            } catch (IOException ex) {
                throw new RuntimeException(ex);
            }
        });

        int result = Result.formingMagicSquare(s);

        bufferedWriter.write(String.valueOf(result));
        bufferedWriter.newLine();

        bufferedReader.close();
        bufferedWriter.close();
    }
}

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